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49247265723833 is a prime number
BaseRepresentation
bin10110011001010010001011…
…10001111001010110111001
320110100222210121211002000102
423030221011301321112321
522423331400011130313
6252423514225245145
713241666103560162
oct1314510561712671
9213328717732012
1049247265723833
111476771469a281
1256345497937b5
132162cc6bbb438
14c2381a7ba769
155a607b15ba58
hex2cca45c795b9

49247265723833 has 2 divisors, whose sum is σ = 49247265723834. Its totient is φ = 49247265723832.

The previous prime is 49247265723827. The next prime is 49247265724061. The reversal of 49247265723833 is 33832756274294.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29994757702009 + 19252508021824 = 5476747^2 + 4387768^2 .

It is a cyclic number.

It is not a de Polignac number, because 49247265723833 - 224 = 49247248946617 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 49247265723833.

It is not a weakly prime, because it can be changed into another prime (49247265723133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24623632861916 + 24623632861917.

It is an arithmetic number, because the mean of its divisors is an integer number (24623632861917).

Almost surely, 249247265723833 is an apocalyptic number.

It is an amenable number.

49247265723833 is a deficient number, since it is larger than the sum of its proper divisors (1).

49247265723833 is an equidigital number, since it uses as much as digits as its factorization.

49247265723833 is an evil number, because the sum of its binary digits is even.

The product of its digits is 365783040, while the sum is 65.

The spelling of 49247265723833 in words is "forty-nine trillion, two hundred forty-seven billion, two hundred sixty-five million, seven hundred twenty-three thousand, eight hundred thirty-three".