Base | Representation |
---|---|
bin | 1110010101101001001… |
… | …11110100011111100011 |
3 | 1202002122002022210220101 |
4 | 13022310213310133203 |
5 | 31032430042444001 |
6 | 1014153500523231 |
7 | 50410330041022 |
oct | 7126447643743 |
9 | 1662562283811 |
10 | 492656609251 |
11 | 17aa308a3324 |
12 | 7b591850517 |
13 | 375c3964051 |
14 | 19bb7c3a8b9 |
15 | cc360d8a01 |
hex | 72b49f47e3 |
492656609251 has 2 divisors, whose sum is σ = 492656609252. Its totient is φ = 492656609250.
The previous prime is 492656609233. The next prime is 492656609309. The reversal of 492656609251 is 152906656294.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 492656609251 - 221 = 492654512099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 492656609192 and 492656609201.
It is not a weakly prime, because it can be changed into another prime (492656609051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246328304625 + 246328304626.
It is an arithmetic number, because the mean of its divisors is an integer number (246328304626).
Almost surely, 2492656609251 is an apocalyptic number.
492656609251 is a deficient number, since it is larger than the sum of its proper divisors (1).
492656609251 is an equidigital number, since it uses as much as digits as its factorization.
492656609251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6998400, while the sum is 55.
The spelling of 492656609251 in words is "four hundred ninety-two billion, six hundred fifty-six million, six hundred nine thousand, two hundred fifty-one".
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