Base | Representation |
---|---|
bin | 1110010101110110001… |
… | …00000100111001010011 |
3 | 1202002220121200100202221 |
4 | 13022323010010321103 |
5 | 31033140224223023 |
6 | 1014212321121511 |
7 | 50413111445266 |
oct | 7127304047123 |
9 | 1662817610687 |
10 | 492764679763 |
11 | 17aa868a72a4 |
12 | 7b601a89297 |
13 | 376101720b5 |
14 | 19bc832ccdd |
15 | cc4083485d |
hex | 72bb104e53 |
492764679763 has 2 divisors, whose sum is σ = 492764679764. Its totient is φ = 492764679762.
The previous prime is 492764679731. The next prime is 492764679769. The reversal of 492764679763 is 367976467294.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 492764679763 - 25 = 492764679731 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 492764679692 and 492764679701.
It is not a weakly prime, because it can be changed into another prime (492764679769) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246382339881 + 246382339882.
It is an arithmetic number, because the mean of its divisors is an integer number (246382339882).
Almost surely, 2492764679763 is an apocalyptic number.
492764679763 is a deficient number, since it is larger than the sum of its proper divisors (1).
492764679763 is an equidigital number, since it uses as much as digits as its factorization.
492764679763 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 576108288, while the sum is 70.
The spelling of 492764679763 in words is "four hundred ninety-two billion, seven hundred sixty-four million, six hundred seventy-nine thousand, seven hundred sixty-three".
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