Base | Representation |
---|---|
bin | 101101111011101111… |
… | …011111001111100011 |
3 | 11201022020120110202221 |
4 | 231323233133033203 |
5 | 1302002043432223 |
6 | 34354013251511 |
7 | 3364132630051 |
oct | 557357371743 |
9 | 151266513687 |
10 | 49320686563 |
11 | 19a0a272895 |
12 | 9685493b97 |
13 | 48600c4405 |
14 | 255c41d1d1 |
15 | 1439e0bb5d |
hex | b7bbdf3e3 |
49320686563 has 2 divisors, whose sum is σ = 49320686564. Its totient is φ = 49320686562.
The previous prime is 49320686521. The next prime is 49320686581. The reversal of 49320686563 is 36568602394.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49320686563 - 225 = 49287132131 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 49320686563.
It is not a weakly prime, because it can be changed into another prime (49320686593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24660343281 + 24660343282.
It is an arithmetic number, because the mean of its divisors is an integer number (24660343282).
Almost surely, 249320686563 is an apocalyptic number.
49320686563 is a deficient number, since it is larger than the sum of its proper divisors (1).
49320686563 is an equidigital number, since it uses as much as digits as its factorization.
49320686563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5598720, while the sum is 52.
The spelling of 49320686563 in words is "forty-nine billion, three hundred twenty million, six hundred eighty-six thousand, five hundred sixty-three".
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