Base | Representation |
---|---|
bin | 100011111000110000011… |
… | …0000111101010010110001 |
3 | 122110111222200211100121011 |
4 | 1013301200300331102301 |
5 | 1121302214422340023 |
6 | 14253501551030521 |
7 | 1016225436302206 |
oct | 107614060752261 |
9 | 18414880740534 |
10 | 4932245902513 |
11 | 1631832257276 |
12 | 677a9b20b441 |
13 | 29a155030617 |
14 | 130a17159cad |
15 | 8847439850d |
hex | 47c60c3d4b1 |
4932245902513 has 2 divisors, whose sum is σ = 4932245902514. Its totient is φ = 4932245902512.
The previous prime is 4932245902481. The next prime is 4932245902637. The reversal of 4932245902513 is 3152095422394.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3678524530704 + 1253721371809 = 1917948^2 + 1119697^2 .
It is a cyclic number.
It is not a de Polignac number, because 4932245902513 - 25 = 4932245902481 is a prime.
It is not a weakly prime, because it can be changed into another prime (4932245932513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2466122951256 + 2466122951257.
It is an arithmetic number, because the mean of its divisors is an integer number (2466122951257).
Almost surely, 24932245902513 is an apocalyptic number.
It is an amenable number.
4932245902513 is a deficient number, since it is larger than the sum of its proper divisors (1).
4932245902513 is an equidigital number, since it uses as much as digits as its factorization.
4932245902513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2332800, while the sum is 49.
The spelling of 4932245902513 in words is "four trillion, nine hundred thirty-two billion, two hundred forty-five million, nine hundred two thousand, five hundred thirteen".
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