4932810097253 has 4 divisors (see below), whose sum is σ = 5091933003648. Its totient is φ = 4773687190860.

The previous prime is 4932810097219. The next prime is 4932810097279. The reversal of 4932810097253 is 3527900182394.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4932810097253 - 2⁸ = 4932810096997 is a prime.

It is a super-2 number, since 2×4932810097253² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4932810097195 and 4932810097204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4932810027253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79561453151 + ... + 79561453212.

It is an arithmetic number, because the mean of its divisors is an integer number (1272983250912).

Almost surely, 2^{4932810097253} is an apocalyptic number.

It is an amenable number.

4932810097253 is a deficient number, since it is larger than the sum of its proper divisors (159122906395).

4932810097253 is a wasteful number, since it uses less digits than its factorization.

4932810097253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159122906394.

The product of its (nonzero) digits is 3265920, while the sum is 53.

The spelling of 4932810097253 in words is "four trillion, nine hundred thirty-two billion, eight hundred ten million, ninety-seven thousand, two hundred fifty-three".