Base | Representation |
---|---|
bin | 100011111001000111101… |
… | …0000111110110100011011 |
3 | 122110121000001210220210212 |
4 | 1013302033100332310123 |
5 | 1121310314132034212 |
6 | 14254111220201335 |
7 | 1016253661400516 |
oct | 107621720766433 |
9 | 18417001726725 |
10 | 4933026049307 |
11 | 16320a2668094 |
12 | 67807853924b |
13 | 29a24a851b45 |
14 | 130a8c9d7d7d |
15 | 884bcaece22 |
hex | 47c8f43ed1b |
4933026049307 has 16 divisors (see below), whose sum is σ = 4975197086400. Its totient is φ = 4890947719680.
The previous prime is 4933026049271. The next prime is 4933026049349. The reversal of 4933026049307 is 7039406203394.
It is a happy number.
4933026049307 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 4933026049307 - 218 = 4933025787163 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4933026049387) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 847450457 + ... + 847456277.
It is an arithmetic number, because the mean of its divisors is an integer number (310949817900).
Almost surely, 24933026049307 is an apocalyptic number.
4933026049307 is a deficient number, since it is larger than the sum of its proper divisors (42171037093).
4933026049307 is a wasteful number, since it uses less digits than its factorization.
4933026049307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12566.
The product of its (nonzero) digits is 2939328, while the sum is 50.
The spelling of 4933026049307 in words is "four trillion, nine hundred thirty-three billion, twenty-six million, forty-nine thousand, three hundred seven".
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