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49341138000 = 24353721121973
BaseRepresentation
bin101101111100111101…
…100000010001010000
311201100200001111212120
4231330331200101100
51302022312404000
634400023454240
73364501516200
oct557475402120
9151320044776
1049341138000
1119a1a871300
1296902b7380
13486440515b
142561024400
15143baeb6a0
hexb7cf60450

49341138000 has 1440 divisors, whose sum is σ = 217037358720. Its totient is φ = 9580032000.

The previous prime is 49341137999. The next prime is 49341138029. The reversal of 49341138000 is 83114394.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 675905964 + ... + 675906036.

It is an arithmetic number, because the mean of its divisors is an integer number (150720388).

Almost surely, 249341138000 is an apocalyptic number.

49341138000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 49341138000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (108518679360).

49341138000 is an abundant number, since it is smaller than the sum of its proper divisors (167696220720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

49341138000 is a wasteful number, since it uses less digits than its factorization.

49341138000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 154 (or 120 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 33.

The spelling of 49341138000 in words is "forty-nine billion, three hundred forty-one million, one hundred thirty-eight thousand".