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493412713697 is a prime number
BaseRepresentation
bin1110010111000011011…
…00001000010011100001
31202011120210001220012202
413023201230020103201
531041002123314242
61014400510502545
750435140603121
oct7134154102341
91664523056182
10493412713697
11180289682832
127b762b04a55
13376b44b8227
1419c4a41ac81
15cc7c68e932
hex72e1b084e1

493412713697 has 2 divisors, whose sum is σ = 493412713698. Its totient is φ = 493412713696.

The previous prime is 493412713649. The next prime is 493412713723. The reversal of 493412713697 is 796317214394.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 463868604241 + 29544109456 = 681079^2 + 171884^2 .

It is a cyclic number.

It is not a de Polignac number, because 493412713697 - 28 = 493412713441 is a prime.

It is a super-2 number, since 2×4934127136972 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (493412713897) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246706356848 + 246706356849.

It is an arithmetic number, because the mean of its divisors is an integer number (246706356849).

Almost surely, 2493412713697 is an apocalyptic number.

It is an amenable number.

493412713697 is a deficient number, since it is larger than the sum of its proper divisors (1).

493412713697 is an equidigital number, since it uses as much as digits as its factorization.

493412713697 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6858432, while the sum is 56.

The spelling of 493412713697 in words is "four hundred ninety-three billion, four hundred twelve million, seven hundred thirteen thousand, six hundred ninety-seven".