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49344431399 = 163302726573
BaseRepresentation
bin101101111101001010…
…000100010100100111
311201100220020211120022
4231331022010110213
51302024133301044
634400222225355
73364541514014
oct557512042447
9151326224508
1049344431399
1119a2171071a
12969142525b
134864cb9203
14256164070b
15143c04c3ee
hexb7d284527

49344431399 has 4 divisors (see below), whose sum is σ = 49647158136. Its totient is φ = 49041704664.

The previous prime is 49344431377. The next prime is 49344431407. The reversal of 49344431399 is 99313444394.

49344431399 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-49344431399 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 49344431399.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (49344431309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151363124 + ... + 151363449.

It is an arithmetic number, because the mean of its divisors is an integer number (12411789534).

Almost surely, 249344431399 is an apocalyptic number.

49344431399 is a deficient number, since it is larger than the sum of its proper divisors (302726737).

49344431399 is a wasteful number, since it uses less digits than its factorization.

49344431399 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 302726736.

The product of its digits is 5038848, while the sum is 53.

The spelling of 49344431399 in words is "forty-nine billion, three hundred forty-four million, four hundred thirty-one thousand, three hundred ninety-nine".

Divisors: 1 163 302726573 49344431399