Base | Representation |
---|---|
bin | 10110011100101101111000… |
… | …11110100111100101101011 |
3 | 20110210021021010222222100011 |
4 | 23032112330132213211223 |
5 | 22432244433121313021 |
6 | 252554023010152351 |
7 | 13253343126326254 |
oct | 1316267436474553 |
9 | 213707233888304 |
10 | 49365221276011 |
11 | 148027445094a3 |
12 | 56533888826b7 |
13 | 2171174668264 |
14 | c2940a3b7b2b |
15 | 5a91818bede1 |
hex | 2ce5bc7a796b |
49365221276011 has 2 divisors, whose sum is σ = 49365221276012. Its totient is φ = 49365221276010.
The previous prime is 49365221275949. The next prime is 49365221276053. The reversal of 49365221276011 is 11067212256394.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49365221276011 - 215 = 49365221243243 is a prime.
It is not a weakly prime, because it can be changed into another prime (49365221276711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24682610638005 + 24682610638006.
It is an arithmetic number, because the mean of its divisors is an integer number (24682610638006).
Almost surely, 249365221276011 is an apocalyptic number.
49365221276011 is a deficient number, since it is larger than the sum of its proper divisors (1).
49365221276011 is an equidigital number, since it uses as much as digits as its factorization.
49365221276011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 49.
The spelling of 49365221276011 in words is "forty-nine trillion, three hundred sixty-five billion, two hundred twenty-one million, two hundred seventy-six thousand, eleven".
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