Base | Representation |
---|---|
bin | 1110010111100010010… |
… | …11100011111010000001 |
3 | 1202012020220010001220201 |
4 | 13023301023203322001 |
5 | 31042020142031312 |
6 | 1014442353205201 |
7 | 50444444650414 |
oct | 7136113437201 |
9 | 1665226101821 |
10 | 493672611457 |
11 | 180402356873 |
12 | 7b815b60801 |
13 | 377262b4a9c |
14 | 19c72b51b7b |
15 | cc953cb557 |
hex | 72f12e3e81 |
493672611457 has 2 divisors, whose sum is σ = 493672611458. Its totient is φ = 493672611456.
The previous prime is 493672611433. The next prime is 493672611469. The reversal of 493672611457 is 754116276394.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 450262472256 + 43410139201 = 671016^2 + 208351^2 .
It is a cyclic number.
It is not a de Polignac number, because 493672611457 - 231 = 491525127809 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 493672611398 and 493672611407.
It is not a weakly prime, because it can be changed into another prime (493672617457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246836305728 + 246836305729.
It is an arithmetic number, because the mean of its divisors is an integer number (246836305729).
Almost surely, 2493672611457 is an apocalyptic number.
It is an amenable number.
493672611457 is a deficient number, since it is larger than the sum of its proper divisors (1).
493672611457 is an equidigital number, since it uses as much as digits as its factorization.
493672611457 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7620480, while the sum is 55.
The spelling of 493672611457 in words is "four hundred ninety-three billion, six hundred seventy-two million, six hundred eleven thousand, four hundred fifty-seven".
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