Base | Representation |
---|---|
bin | 100011111011010101111… |
… | …0101111101001100010001 |
3 | 122111001022210201200112112 |
4 | 1013312223311331030101 |
5 | 1121400103410040223 |
6 | 14300221052435105 |
7 | 1016513204330303 |
oct | 107665365751421 |
9 | 18431283650475 |
10 | 4937800471313 |
11 | 1634122701aa6 |
12 | 678b8b478a95 |
13 | 29a82ba3c118 |
14 | 130dc2b39973 |
15 | 8869bd46778 |
hex | 47dabd7d311 |
4937800471313 has 2 divisors, whose sum is σ = 4937800471314. Its totient is φ = 4937800471312.
The previous prime is 4937800471297. The next prime is 4937800471349. The reversal of 4937800471313 is 3131740087394.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4862166121024 + 75634350289 = 2205032^2 + 275017^2 .
It is a cyclic number.
It is not a de Polignac number, because 4937800471313 - 24 = 4937800471297 is a prime.
It is not a weakly prime, because it can be changed into another prime (4937800473313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2468900235656 + 2468900235657.
It is an arithmetic number, because the mean of its divisors is an integer number (2468900235657).
Almost surely, 24937800471313 is an apocalyptic number.
It is an amenable number.
4937800471313 is a deficient number, since it is larger than the sum of its proper divisors (1).
4937800471313 is an equidigital number, since it uses as much as digits as its factorization.
4937800471313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1524096, while the sum is 50.
The spelling of 4937800471313 in words is "four trillion, nine hundred thirty-seven billion, eight hundred million, four hundred seventy-one thousand, three hundred thirteen".
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