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4939700107 is a prime number
BaseRepresentation
bin1001001100110110…
…11101011110001011
3110202020220202122211
410212123131132023
540104030400412
62134054525551
7233260521016
oct44633353613
913666822584
104939700107
112105371891
12b5a3668b7
13609508294
1434c08637d
151dd9e4ca7
hex1266dd78b

4939700107 has 2 divisors, whose sum is σ = 4939700108. Its totient is φ = 4939700106.

The previous prime is 4939700083. The next prime is 4939700113. The reversal of 4939700107 is 7010079394.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4939700107 - 211 = 4939698059 is a prime.

It is a super-2 number, since 2×49397001072 = 48801274294191622898, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4939700107.

It is not a weakly prime, because it can be changed into another prime (4939700137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2469850053 + 2469850054.

It is an arithmetic number, because the mean of its divisors is an integer number (2469850054).

Almost surely, 24939700107 is an apocalyptic number.

4939700107 is a deficient number, since it is larger than the sum of its proper divisors (1).

4939700107 is an equidigital number, since it uses as much as digits as its factorization.

4939700107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 47628, while the sum is 40.

The square root of 4939700107 is about 70283.0001280537. Note that the first 3 decimals coincide. The cubic root of 4939700107 is about 1703.0740351237.

The spelling of 4939700107 in words is "four billion, nine hundred thirty-nine million, seven hundred thousand, one hundred seven".