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4940961451 is a prime number
BaseRepresentation
bin1001001101000000…
…10001011010101011
3110202100021211220021
410212200101122223
540104341231301
62134141541311
7233304323266
oct44640213253
913670254807
104940961451
112106053518
12b5a874837
1360985a43a
1434c2d3cdd
151ddb938a1
hex1268116ab

4940961451 has 2 divisors, whose sum is σ = 4940961452. Its totient is φ = 4940961450.

The previous prime is 4940961439. The next prime is 4940961503. The reversal of 4940961451 is 1541690494.

4940961451 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4940961451 - 27 = 4940961323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4940961398 and 4940961407.

It is not a weakly prime, because it can be changed into another prime (4940961401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2470480725 + 2470480726.

It is an arithmetic number, because the mean of its divisors is an integer number (2470480726).

Almost surely, 24940961451 is an apocalyptic number.

4940961451 is a deficient number, since it is larger than the sum of its proper divisors (1).

4940961451 is an equidigital number, since it uses as much as digits as its factorization.

4940961451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 43.

The square root of 4940961451 is about 70291.9728774204. The cubic root of 4940961451 is about 1703.2189818041.

The spelling of 4940961451 in words is "four billion, nine hundred forty million, nine hundred sixty-one thousand, four hundred fifty-one".