Base | Representation |
---|---|
bin | 1001001101000000… |
… | …10001011010101011 |
3 | 110202100021211220021 |
4 | 10212200101122223 |
5 | 40104341231301 |
6 | 2134141541311 |
7 | 233304323266 |
oct | 44640213253 |
9 | 13670254807 |
10 | 4940961451 |
11 | 2106053518 |
12 | b5a874837 |
13 | 60985a43a |
14 | 34c2d3cdd |
15 | 1ddb938a1 |
hex | 1268116ab |
4940961451 has 2 divisors, whose sum is σ = 4940961452. Its totient is φ = 4940961450.
The previous prime is 4940961439. The next prime is 4940961503. The reversal of 4940961451 is 1541690494.
4940961451 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4940961451 - 27 = 4940961323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4940961398 and 4940961407.
It is not a weakly prime, because it can be changed into another prime (4940961401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2470480725 + 2470480726.
It is an arithmetic number, because the mean of its divisors is an integer number (2470480726).
Almost surely, 24940961451 is an apocalyptic number.
4940961451 is a deficient number, since it is larger than the sum of its proper divisors (1).
4940961451 is an equidigital number, since it uses as much as digits as its factorization.
4940961451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 43.
The square root of 4940961451 is about 70291.9728774204. The cubic root of 4940961451 is about 1703.2189818041.
The spelling of 4940961451 in words is "four billion, nine hundred forty million, nine hundred sixty-one thousand, four hundred fifty-one".
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