Base | Representation |
---|---|
bin | 10110011110001001011011… |
… | …10011001010111110101001 |
3 | 20110221222010012121000020112 |
4 | 23033010231303022332221 |
5 | 22434101110441121023 |
6 | 253032351420304105 |
7 | 13260033040231061 |
oct | 1317045563127651 |
9 | 213858105530215 |
10 | 49414367129513 |
11 | 14821574018651 |
12 | 5660a036a2035 |
13 | 21759a7477549 |
14 | c2b94d4c63a1 |
15 | 5aa5ab294478 |
hex | 2cf12dccafa9 |
49414367129513 has 2 divisors, whose sum is σ = 49414367129514. Its totient is φ = 49414367129512.
The previous prime is 49414367129473. The next prime is 49414367129537. The reversal of 49414367129513 is 31592176341494.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47694313895449 + 1720053234064 = 6906107^2 + 1311508^2 .
It is a cyclic number.
It is not a de Polignac number, because 49414367129513 - 216 = 49414367063977 is a prime.
It is not a weakly prime, because it can be changed into another prime (49414367129563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24707183564756 + 24707183564757.
It is an arithmetic number, because the mean of its divisors is an integer number (24707183564757).
Almost surely, 249414367129513 is an apocalyptic number.
It is an amenable number.
49414367129513 is a deficient number, since it is larger than the sum of its proper divisors (1).
49414367129513 is an equidigital number, since it uses as much as digits as its factorization.
49414367129513 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19595520, while the sum is 59.
The spelling of 49414367129513 in words is "forty-nine trillion, four hundred fourteen billion, three hundred sixty-seven million, one hundred twenty-nine thousand, five hundred thirteen".
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