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49414367129513 is a prime number
BaseRepresentation
bin10110011110001001011011…
…10011001010111110101001
320110221222010012121000020112
423033010231303022332221
522434101110441121023
6253032351420304105
713260033040231061
oct1317045563127651
9213858105530215
1049414367129513
1114821574018651
125660a036a2035
1321759a7477549
14c2b94d4c63a1
155aa5ab294478
hex2cf12dccafa9

49414367129513 has 2 divisors, whose sum is σ = 49414367129514. Its totient is φ = 49414367129512.

The previous prime is 49414367129473. The next prime is 49414367129537. The reversal of 49414367129513 is 31592176341494.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47694313895449 + 1720053234064 = 6906107^2 + 1311508^2 .

It is a cyclic number.

It is not a de Polignac number, because 49414367129513 - 216 = 49414367063977 is a prime.

It is not a weakly prime, because it can be changed into another prime (49414367129563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24707183564756 + 24707183564757.

It is an arithmetic number, because the mean of its divisors is an integer number (24707183564757).

Almost surely, 249414367129513 is an apocalyptic number.

It is an amenable number.

49414367129513 is a deficient number, since it is larger than the sum of its proper divisors (1).

49414367129513 is an equidigital number, since it uses as much as digits as its factorization.

49414367129513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 19595520, while the sum is 59.

The spelling of 49414367129513 in words is "forty-nine trillion, four hundred fourteen billion, three hundred sixty-seven million, one hundred twenty-nine thousand, five hundred thirteen".