Base | Representation |
---|---|
bin | 10110011110111001001000… |
… | …00110100000100001000011 |
3 | 20111001102012210212111110202 |
4 | 23033130210012200201003 |
5 | 22440011031400330313 |
6 | 253052224405315415 |
7 | 13261630436054003 |
oct | 1317344406404103 |
9 | 214042183774422 |
10 | 49439974230083 |
11 | 14831414612288 |
12 | 566596b405b6b |
13 | 21782286c4568 |
14 | c2cc9c344003 |
15 | 5ab0a93d8558 |
hex | 2cf7241a0843 |
49439974230083 has 2 divisors, whose sum is σ = 49439974230084. Its totient is φ = 49439974230082.
The previous prime is 49439974230079. The next prime is 49439974230107. The reversal of 49439974230083 is 38003247993494.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49439974230083 - 22 = 49439974230079 is a prime.
It is a super-2 number, since 2×494399742300832 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (49439974232083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24719987115041 + 24719987115042.
It is an arithmetic number, because the mean of its divisors is an integer number (24719987115042).
Almost surely, 249439974230083 is an apocalyptic number.
49439974230083 is a deficient number, since it is larger than the sum of its proper divisors (1).
49439974230083 is an equidigital number, since it uses as much as digits as its factorization.
49439974230083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 141087744, while the sum is 65.
The spelling of 49439974230083 in words is "forty-nine trillion, four hundred thirty-nine billion, nine hundred seventy-four million, two hundred thirty thousand, eighty-three".
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