Base | Representation |
---|---|
bin | 100011111110011000011… |
… | …0010111000000111000001 |
3 | 122111200011120122221112112 |
4 | 1013330300302320013001 |
5 | 1122001434424013324 |
6 | 14303220401305105 |
7 | 1020134002402406 |
oct | 107746062700701 |
9 | 18450146587475 |
10 | 4944326001089 |
11 | 1636971147112 |
12 | 67a2b0935195 |
13 | 29b32b95b347 |
14 | 1314416682ad |
15 | 8892eb8bc0e |
hex | 47f30cb81c1 |
4944326001089 has 2 divisors, whose sum is σ = 4944326001090. Its totient is φ = 4944326001088.
The previous prime is 4944326001023. The next prime is 4944326001119. The reversal of 4944326001089 is 9801006234494.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4782728433025 + 161597568064 = 2186945^2 + 401992^2 .
It is a cyclic number.
It is not a de Polignac number, because 4944326001089 - 212 = 4944325996993 is a prime.
It is not a weakly prime, because it can be changed into another prime (4944326001019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2472163000544 + 2472163000545.
It is an arithmetic number, because the mean of its divisors is an integer number (2472163000545).
Almost surely, 24944326001089 is an apocalyptic number.
It is an amenable number.
4944326001089 is a deficient number, since it is larger than the sum of its proper divisors (1).
4944326001089 is an equidigital number, since it uses as much as digits as its factorization.
4944326001089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1492992, while the sum is 50.
The spelling of 4944326001089 in words is "four trillion, nine hundred forty-four billion, three hundred twenty-six million, one thousand, eighty-nine".
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