Base | Representation |
---|---|
bin | 100011111110011001110… |
… | …0010001100000000000001 |
3 | 122111200021210010210020111 |
4 | 1013330303202030000001 |
5 | 1122002033210122021 |
6 | 14303225122311321 |
7 | 1020135101130025 |
oct | 107746342140001 |
9 | 18450253123214 |
10 | 4944371957761 |
11 | 1636995086035 |
12 | 67a3041b8541 |
13 | 29b33832c242 |
14 | 1314477cc385 |
15 | 88933c188e1 |
hex | 47f3388c001 |
4944371957761 has 2 divisors, whose sum is σ = 4944371957762. Its totient is φ = 4944371957760.
The previous prime is 4944371957747. The next prime is 4944371957773. The reversal of 4944371957761 is 1677591734494.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3095435578225 + 1848936379536 = 1759385^2 + 1359756^2 .
It is a cyclic number.
It is not a de Polignac number, because 4944371957761 - 221 = 4944369860609 is a prime.
It is not a weakly prime, because it can be changed into another prime (4944371957461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2472185978880 + 2472185978881.
It is an arithmetic number, because the mean of its divisors is an integer number (2472185978881).
Almost surely, 24944371957761 is an apocalyptic number.
It is an amenable number.
4944371957761 is a deficient number, since it is larger than the sum of its proper divisors (1).
4944371957761 is an equidigital number, since it uses as much as digits as its factorization.
4944371957761 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 160030080, while the sum is 67.
The spelling of 4944371957761 in words is "four trillion, nine hundred forty-four billion, three hundred seventy-one million, nine hundred fifty-seven thousand, seven hundred sixty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •