Base | Representation |
---|---|
bin | 111000001101101000000010… |
… | …1100111111111011111111101 |
3 | 2101211201022222002120102100010 |
4 | 1300123100011213333133331 |
5 | 1004302113101243320433 |
6 | 4511340553511253433 |
7 | 206102054546332224 |
oct | 16033200547773775 |
9 | 2354638862512303 |
10 | 494453909354493 |
11 | 1336037a8497750 |
12 | 4755859197a279 |
13 | 182b8a5a61696a |
14 | 8a159a8439cbb |
15 | 3c26d33020e63 |
hex | 1c1b4059ff7fd |
494453909354493 has 64 divisors (see below), whose sum is σ = 752680145387520. Its totient is φ = 285798647428800.
The previous prime is 494453909354459. The next prime is 494453909354497. The reversal of 494453909354493 is 394453909354494.
It is a de Polignac number, because none of the positive numbers 2k-494453909354493 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (494453909354497) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 579325848 + ... + 580178718.
It is an arithmetic number, because the mean of its divisors is an integer number (11760627271680).
Almost surely, 2494453909354493 is an apocalyptic number.
It is an amenable number.
494453909354493 is a deficient number, since it is larger than the sum of its proper divisors (258226236033027).
494453909354493 is a wasteful number, since it uses less digits than its factorization.
494453909354493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 855150.
The product of its (nonzero) digits is 4534963200, while the sum is 75.
Subtracting from 494453909354493 its reverse (394453909354494), we obtain a palindrome (99999999999999).
The spelling of 494453909354493 in words is "four hundred ninety-four trillion, four hundred fifty-three billion, nine hundred nine million, three hundred fifty-four thousand, four hundred ninety-three".
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