Base | Representation |
---|---|
bin | 10110011111001101101101… |
… | …00100110111110110001011 |
3 | 20111002110201201102221101211 |
4 | 23033212312210313312023 |
5 | 22440201143012114331 |
6 | 253101252524553551 |
7 | 13262501262123001 |
oct | 1317466644676613 |
9 | 214073651387354 |
10 | 49451021598091 |
11 | 14836073563393 |
12 | 5667b330b28b7 |
13 | 21792993952c9 |
14 | c2d629624a71 |
15 | 5ab5041d28b1 |
hex | 2cf9b6937d8b |
49451021598091 has 2 divisors, whose sum is σ = 49451021598092. Its totient is φ = 49451021598090.
The previous prime is 49451021598079. The next prime is 49451021598101. The reversal of 49451021598091 is 19089512015494.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49451021598091 - 223 = 49451013209483 is a prime.
It is a super-3 number, since 3×494510215980913 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (49451021598691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24725510799045 + 24725510799046.
It is an arithmetic number, because the mean of its divisors is an integer number (24725510799046).
Almost surely, 249451021598091 is an apocalyptic number.
49451021598091 is a deficient number, since it is larger than the sum of its proper divisors (1).
49451021598091 is an equidigital number, since it uses as much as digits as its factorization.
49451021598091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4665600, while the sum is 58.
The spelling of 49451021598091 in words is "forty-nine trillion, four hundred fifty-one billion, twenty-one million, five hundred ninety-eight thousand, ninety-one".
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