Base | Representation |
---|---|
bin | 101110000011110001… |
… | …010110001110100011 |
3 | 11201122122001012102021 |
4 | 232003301112032203 |
5 | 1302241040013101 |
6 | 34415224402311 |
7 | 3400356615211 |
oct | 560361261643 |
9 | 151578035367 |
10 | 49455391651 |
11 | 19a79308806 |
12 | 9702616397 |
13 | 4881c99673 |
14 | 2572285cb1 |
15 | 1446b695a1 |
hex | b83c563a3 |
49455391651 has 2 divisors, whose sum is σ = 49455391652. Its totient is φ = 49455391650.
The previous prime is 49455391633. The next prime is 49455391673. The reversal of 49455391651 is 15619355494.
49455391651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49455391651 - 213 = 49455383459 is a prime.
It is not a weakly prime, because it can be changed into another prime (49455391151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24727695825 + 24727695826.
It is an arithmetic number, because the mean of its divisors is an integer number (24727695826).
Almost surely, 249455391651 is an apocalyptic number.
49455391651 is a deficient number, since it is larger than the sum of its proper divisors (1).
49455391651 is an equidigital number, since it uses as much as digits as its factorization.
49455391651 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2916000, while the sum is 52.
The spelling of 49455391651 in words is "forty-nine billion, four hundred fifty-five million, three hundred ninety-one thousand, six hundred fifty-one".
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