Base | Representation |
---|---|
bin | 100011111111101100000… |
… | …1100111000011001111111 |
3 | 122111221102022120012221022 |
4 | 1013333120030320121333 |
5 | 1122023212430104434 |
6 | 14304403211454355 |
7 | 1020263415246566 |
oct | 107773014703177 |
9 | 18457368505838 |
10 | 4947134613119 |
11 | 1638082576986 |
12 | 67a9554573bb |
13 | 29b6887b245a |
14 | 13162a690bdd |
15 | 88a4652822e |
hex | 47fd833867f |
4947134613119 has 8 divisors (see below), whose sum is σ = 5014942171200. Its totient is φ = 4879328098176.
The previous prime is 4947134613073. The next prime is 4947134613143. The reversal of 4947134613119 is 9113164317494.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4947134613119 - 228 = 4946866177663 is a prime.
It is a super-2 number, since 2×49471346131192 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4947134613419) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17812682 + ... + 18088280.
It is an arithmetic number, because the mean of its divisors is an integer number (626867771400).
Almost surely, 24947134613119 is an apocalyptic number.
4947134613119 is a deficient number, since it is larger than the sum of its proper divisors (67807558081).
4947134613119 is a wasteful number, since it uses less digits than its factorization.
4947134613119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 521569.
The product of its digits is 1959552, while the sum is 53.
The spelling of 4947134613119 in words is "four trillion, nine hundred forty-seven billion, one hundred thirty-four million, six hundred thirteen thousand, one hundred nineteen".
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