Base | Representation |
---|---|
bin | 100100000001010110101… |
… | …1111001010001101111001 |
3 | 122112021122200211122121212 |
4 | 1020002231133022031321 |
5 | 1122103030003423143 |
6 | 14310154240012505 |
7 | 1020451165522526 |
oct | 110025537121571 |
9 | 18467580748555 |
10 | 4950712951673 |
11 | 163964943a675 |
12 | 67b593901135 |
13 | 29bb08c49b48 |
14 | 131889a0214d |
15 | 88ba575b918 |
hex | 480ad7ca379 |
4950712951673 has 2 divisors, whose sum is σ = 4950712951674. Its totient is φ = 4950712951672.
The previous prime is 4950712951643. The next prime is 4950712951721. The reversal of 4950712951673 is 3761592170594.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4911307525609 + 39405426064 = 2216147^2 + 198508^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4950712951673 is a prime.
It is not a weakly prime, because it can be changed into another prime (4950712951643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2475356475836 + 2475356475837.
It is an arithmetic number, because the mean of its divisors is an integer number (2475356475837).
Almost surely, 24950712951673 is an apocalyptic number.
It is an amenable number.
4950712951673 is a deficient number, since it is larger than the sum of its proper divisors (1).
4950712951673 is an equidigital number, since it uses as much as digits as its factorization.
4950712951673 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14288400, while the sum is 59.
The spelling of 4950712951673 in words is "four trillion, nine hundred fifty billion, seven hundred twelve million, nine hundred fifty-one thousand, six hundred seventy-three".
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