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495505000447 = 3471427968301
BaseRepresentation
bin1110011010111100110…
…01100100011111111111
31202100222121002002001121
413031132121210133333
531104243240003242
61015344251451411
750541035003362
oct7153631443777
91670877062047
10495505000447
11181162722836
1280047756b67
1337958b05322
1419da825a0d9
15cd511d1667
hex735e6647ff

495505000447 has 4 divisors (see below), whose sum is σ = 496932969096. Its totient is φ = 494077031800.

The previous prime is 495505000423. The next prime is 495505000453. The reversal of 495505000447 is 744000505594.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 744000505594 = 2372000252797.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-495505000447 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (495505000547) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 713983804 + ... + 713984497.

It is an arithmetic number, because the mean of its divisors is an integer number (124233242274).

Almost surely, 2495505000447 is an apocalyptic number.

495505000447 is a deficient number, since it is larger than the sum of its proper divisors (1427968649).

495505000447 is a wasteful number, since it uses less digits than its factorization.

495505000447 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1427968648.

The product of its (nonzero) digits is 504000, while the sum is 43.

The spelling of 495505000447 in words is "four hundred ninety-five billion, five hundred five million, four hundred forty-seven", and thus it is an aban number.

Divisors: 1 347 1427968301 495505000447