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4958116994353 is a prime number
BaseRepresentation
bin100100000100110011011…
…0011010101110100110001
3122112222202200211222202211
41020021212303111310301
51122213210422304403
614313421050212121
71021132522042015
oct110114663256461
918488680758684
104958116994353
1116417a8870506
12680abb424041
1329c718b7b4a3
14131d8d096545
1588e8a78706d
hex48266cd5d31

4958116994353 has 2 divisors, whose sum is σ = 4958116994354. Its totient is φ = 4958116994352.

The previous prime is 4958116994293. The next prime is 4958116994381. The reversal of 4958116994353 is 3534996118594.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3359493083664 + 1598623910689 = 1832892^2 + 1264367^2 .

It is a cyclic number.

It is not a de Polignac number, because 4958116994353 - 237 = 4820678040881 is a prime.

It is not a weakly prime, because it can be changed into another prime (4958116904353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2479058497176 + 2479058497177.

It is an arithmetic number, because the mean of its divisors is an integer number (2479058497177).

Almost surely, 24958116994353 is an apocalyptic number.

It is an amenable number.

4958116994353 is a deficient number, since it is larger than the sum of its proper divisors (1).

4958116994353 is an equidigital number, since it uses as much as digits as its factorization.

4958116994353 is an evil number, because the sum of its binary digits is even.

The product of its digits is 125971200, while the sum is 67.

The spelling of 4958116994353 in words is "four trillion, nine hundred fifty-eight billion, one hundred sixteen million, nine hundred ninety-four thousand, three hundred fifty-three".