Base | Representation |
---|---|
bin | 100100000100110011011… |
… | …0011010101110100110001 |
3 | 122112222202200211222202211 |
4 | 1020021212303111310301 |
5 | 1122213210422304403 |
6 | 14313421050212121 |
7 | 1021132522042015 |
oct | 110114663256461 |
9 | 18488680758684 |
10 | 4958116994353 |
11 | 16417a8870506 |
12 | 680abb424041 |
13 | 29c718b7b4a3 |
14 | 131d8d096545 |
15 | 88e8a78706d |
hex | 48266cd5d31 |
4958116994353 has 2 divisors, whose sum is σ = 4958116994354. Its totient is φ = 4958116994352.
The previous prime is 4958116994293. The next prime is 4958116994381. The reversal of 4958116994353 is 3534996118594.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3359493083664 + 1598623910689 = 1832892^2 + 1264367^2 .
It is a cyclic number.
It is not a de Polignac number, because 4958116994353 - 237 = 4820678040881 is a prime.
It is not a weakly prime, because it can be changed into another prime (4958116904353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2479058497176 + 2479058497177.
It is an arithmetic number, because the mean of its divisors is an integer number (2479058497177).
Almost surely, 24958116994353 is an apocalyptic number.
It is an amenable number.
4958116994353 is a deficient number, since it is larger than the sum of its proper divisors (1).
4958116994353 is an equidigital number, since it uses as much as digits as its factorization.
4958116994353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 125971200, while the sum is 67.
The spelling of 4958116994353 in words is "four trillion, nine hundred fifty-eight billion, one hundred sixteen million, nine hundred ninety-four thousand, three hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •