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49584242809 is a prime number
BaseRepresentation
bin101110001011011100…
…111000000001111001
311201222121111111222101
4232023130320001321
51303022031232214
634440110223401
73403513052443
oct561334700171
9151877444871
1049584242809
111a035015572
1297397b4b61
1348a28a225a
142585427493
15145311c774
hexb8b738079

49584242809 has 2 divisors, whose sum is σ = 49584242810. Its totient is φ = 49584242808.

The previous prime is 49584242777. The next prime is 49584242837. The reversal of 49584242809 is 90824248594.

49584242809 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43898630400 + 5685612409 = 209520^2 + 75403^2 .

It is a cyclic number.

It is not a de Polignac number, because 49584242809 - 25 = 49584242777 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 49584242809.

It is not a weakly prime, because it can be changed into another prime (49584242849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24792121404 + 24792121405.

It is an arithmetic number, because the mean of its divisors is an integer number (24792121405).

Almost surely, 249584242809 is an apocalyptic number.

It is an amenable number.

49584242809 is a deficient number, since it is larger than the sum of its proper divisors (1).

49584242809 is an equidigital number, since it uses as much as digits as its factorization.

49584242809 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6635520, while the sum is 55.

The spelling of 49584242809 in words is "forty-nine billion, five hundred eighty-four million, two hundred forty-two thousand, eight hundred nine".