Base | Representation |
---|---|
bin | 100100000110100101101… |
… | …1011110100010101111001 |
3 | 122120100200000121122010101 |
4 | 1020031023123310111321 |
5 | 1122244034404412421 |
6 | 14315253433115401 |
7 | 1021326546662041 |
oct | 110151333642571 |
9 | 18510600548111 |
10 | 4961952810361 |
11 | 1643397004888 |
12 | 6817abb58b61 |
13 | 29cbaa775bc1 |
14 | 1322346ac721 |
15 | 891123ca191 |
hex | 4834b6f4579 |
4961952810361 has 2 divisors, whose sum is σ = 4961952810362. Its totient is φ = 4961952810360.
The previous prime is 4961952810341. The next prime is 4961952810389. The reversal of 4961952810361 is 1630182591694.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3555653294736 + 1406299515625 = 1885644^2 + 1185875^2 .
It is a cyclic number.
It is not a de Polignac number, because 4961952810361 - 235 = 4927593071993 is a prime.
It is not a weakly prime, because it can be changed into another prime (4961952810301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2480976405180 + 2480976405181.
It is an arithmetic number, because the mean of its divisors is an integer number (2480976405181).
Almost surely, 24961952810361 is an apocalyptic number.
It is an amenable number.
4961952810361 is a deficient number, since it is larger than the sum of its proper divisors (1).
4961952810361 is an equidigital number, since it uses as much as digits as its factorization.
4961952810361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2799360, while the sum is 55.
The spelling of 4961952810361 in words is "four trillion, nine hundred sixty-one billion, nine hundred fifty-two million, eight hundred ten thousand, three hundred sixty-one".
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