Base | Representation |
---|---|
bin | 100100000110100110111… |
… | …1001000110111110001001 |
3 | 122120100202220012111001021 |
4 | 1020031031321012332021 |
5 | 1122244130433341043 |
6 | 14315301504552441 |
7 | 1021330560313441 |
oct | 110151571067611 |
9 | 18510686174037 |
10 | 4961994043273 |
11 | 1643408307773 |
12 | 681801922721 |
13 | 29cbb6181987 |
14 | 132239d63121 |
15 | 89115d223ed |
hex | 4834de46f89 |
4961994043273 has 2 divisors, whose sum is σ = 4961994043274. Its totient is φ = 4961994043272.
The previous prime is 4961994043267. The next prime is 4961994043277. The reversal of 4961994043273 is 3723404991694.
4961994043273 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2795878279744 + 2166115763529 = 1672088^2 + 1471773^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4961994043273 is a prime.
It is not a weakly prime, because it can be changed into another prime (4961994043277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2480997021636 + 2480997021637.
It is an arithmetic number, because the mean of its divisors is an integer number (2480997021637).
Almost surely, 24961994043273 is an apocalyptic number.
It is an amenable number.
4961994043273 is a deficient number, since it is larger than the sum of its proper divisors (1).
4961994043273 is an equidigital number, since it uses as much as digits as its factorization.
4961994043273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 35271936, while the sum is 61.
The spelling of 4961994043273 in words is "four trillion, nine hundred sixty-one billion, nine hundred ninety-four million, forty-three thousand, two hundred seventy-three".
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