Base | Representation |
---|---|
bin | 10110100100011011110001… |
… | …01001110101000011010111 |
3 | 20111201121122220121122022102 |
4 | 23102031320221311003113 |
5 | 23001121000030231112 |
6 | 253315513340152315 |
7 | 13311450603546311 |
oct | 1322157051650327 |
9 | 214647586548272 |
10 | 49630371336407 |
11 | 148a5138838314 |
12 | 5696846b3869b |
13 | 219017c393714 |
14 | c381a0d127b1 |
15 | 5b0eee790bc2 |
hex | 2d2378a750d7 |
49630371336407 has 4 divisors (see below), whose sum is σ = 49636675214640. Its totient is φ = 49624067458176.
The previous prime is 49630371336389. The next prime is 49630371336419. The reversal of 49630371336407 is 70463317303694.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49630371336407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49630371336467) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3151927307 + ... + 3151943052.
It is an arithmetic number, because the mean of its divisors is an integer number (12409168803660).
Almost surely, 249630371336407 is an apocalyptic number.
49630371336407 is a deficient number, since it is larger than the sum of its proper divisors (6303878233).
49630371336407 is an equidigital number, since it uses as much as digits as its factorization.
49630371336407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6303878232.
The product of its (nonzero) digits is 20575296, while the sum is 56.
The spelling of 49630371336407 in words is "forty-nine trillion, six hundred thirty billion, three hundred seventy-one million, three hundred thirty-six thousand, four hundred seven".
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