Base | Representation |
---|---|
bin | 1001001111101010… |
… | …01101100100110001 |
3 | 110210220012002210112 |
4 | 10213311031210301 |
5 | 40131041243303 |
6 | 2140255111105 |
7 | 233664512225 |
oct | 44765154461 |
9 | 13726162715 |
10 | 4963227953 |
11 | 2117681692 |
12 | b66212495 |
13 | 611355398 |
14 | 35124c785 |
15 | 1e0ae10d8 |
hex | 127d4d931 |
4963227953 has 2 divisors, whose sum is σ = 4963227954. Its totient is φ = 4963227952.
The previous prime is 4963227931. The next prime is 4963227959. The reversal of 4963227953 is 3597223694.
4963227953 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4948841104 + 14386849 = 70348^2 + 3793^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4963227953 is a prime.
It is not a weakly prime, because it can be changed into another prime (4963227959) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2481613976 + 2481613977.
It is an arithmetic number, because the mean of its divisors is an integer number (2481613977).
Almost surely, 24963227953 is an apocalyptic number.
It is an amenable number.
4963227953 is a deficient number, since it is larger than the sum of its proper divisors (1).
4963227953 is an equidigital number, since it uses as much as digits as its factorization.
4963227953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2449440, while the sum is 50.
The square root of 4963227953 is about 70450.1806456165. The cubic root of 4963227953 is about 1705.7736736408.
The spelling of 4963227953 in words is "four billion, nine hundred sixty-three million, two hundred twenty-seven thousand, nine hundred fifty-three".
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