Base | Representation |
---|---|
bin | 100100001000011100001… |
… | …0011000011011000110001 |
3 | 122120201220222012210120012 |
4 | 1020100320103003120301 |
5 | 1122330204214303011 |
6 | 14321152031424305 |
7 | 1021530202412501 |
oct | 110207023033061 |
9 | 18521828183505 |
10 | 4965926712881 |
11 | 1645046193642 |
12 | 68251a985095 |
13 | 2a0391b5aa04 |
14 | 1324d038ba01 |
15 | 892961e7a8b |
hex | 484384c3631 |
4965926712881 has 2 divisors, whose sum is σ = 4965926712882. Its totient is φ = 4965926712880.
The previous prime is 4965926712869. The next prime is 4965926712919. The reversal of 4965926712881 is 1882176295694.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4962161663281 + 3765049600 = 2227591^2 + 61360^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4965926712881 is a prime.
It is a super-2 number, since 2×49659267128812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4965926732881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2482963356440 + 2482963356441.
It is an arithmetic number, because the mean of its divisors is an integer number (2482963356441).
Almost surely, 24965926712881 is an apocalyptic number.
It is an amenable number.
4965926712881 is a deficient number, since it is larger than the sum of its proper divisors (1).
4965926712881 is an equidigital number, since it uses as much as digits as its factorization.
4965926712881 is an evil number, because the sum of its binary digits is even.
The product of its digits is 104509440, while the sum is 68.
The spelling of 4965926712881 in words is "four trillion, nine hundred sixty-five billion, nine hundred twenty-six million, seven hundred twelve thousand, eight hundred eighty-one".
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