Base | Representation |
---|---|
bin | 101110010000011000… |
… | …101000101010000011 |
3 | 11202012101020220022000 |
4 | 232100120220222003 |
5 | 1303204224023342 |
6 | 34452224315043 |
7 | 3405536452563 |
oct | 562030505203 |
9 | 152171226260 |
10 | 49667017347 |
11 | 1a077811282 |
12 | 9761472a83 |
13 | 48b6a9447c |
14 | 2592412da3 |
15 | 145a51d44c |
hex | b90628a83 |
49667017347 has 64 divisors (see below), whose sum is σ = 76725411840. Its totient is φ = 31730400000.
The previous prime is 49667017321. The next prime is 49667017423. The reversal of 49667017347 is 74371076694.
It is not a de Polignac number, because 49667017347 - 27 = 49667017219 is a prime.
It is a super-2 number, since 2×496670173472 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 49667017293 and 49667017302.
It is not an unprimeable number, because it can be changed into a prime (49667017307) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14645022 + ... + 14648412.
It is an arithmetic number, because the mean of its divisors is an integer number (1198834560).
Almost surely, 249667017347 is an apocalyptic number.
49667017347 is a deficient number, since it is larger than the sum of its proper divisors (27058394493).
49667017347 is a wasteful number, since it uses less digits than its factorization.
49667017347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3673 (or 3667 counting only the distinct ones).
The product of its (nonzero) digits is 5334336, while the sum is 54.
The spelling of 49667017347 in words is "forty-nine billion, six hundred sixty-seven million, seventeen thousand, three hundred forty-seven".
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