Base | Representation |
---|---|
bin | 10110100110000111001010… |
… | …01100101111010101000001 |
3 | 20111221010111000220221001221 |
4 | 23103003211030233111001 |
5 | 23003042034403032202 |
6 | 253402210421155041 |
7 | 13315561425613324 |
oct | 1323034514572501 |
9 | 214833430827057 |
10 | 49688027002177 |
11 | 14917634973373 |
12 | 56a5a5785ba81 |
13 | 219573a225195 |
14 | c3acb02b67bb |
15 | 5b27762b6037 |
hex | 2d30e532f541 |
49688027002177 has 2 divisors, whose sum is σ = 49688027002178. Its totient is φ = 49688027002176.
The previous prime is 49688027002091. The next prime is 49688027002217. The reversal of 49688027002177 is 77120072088694.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44468305423936 + 5219721578241 = 6668456^2 + 2284671^2 .
It is a cyclic number.
It is not a de Polignac number, because 49688027002177 - 227 = 49687892784449 is a prime.
It is not a weakly prime, because it can be changed into another prime (49688027000177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24844013501088 + 24844013501089.
It is an arithmetic number, because the mean of its divisors is an integer number (24844013501089).
Almost surely, 249688027002177 is an apocalyptic number.
It is an amenable number.
49688027002177 is a deficient number, since it is larger than the sum of its proper divisors (1).
49688027002177 is an equidigital number, since it uses as much as digits as its factorization.
49688027002177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18966528, while the sum is 61.
The spelling of 49688027002177 in words is "forty-nine trillion, six hundred eighty-eight billion, twenty-seven million, two thousand, one hundred seventy-seven".
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