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496893101233 is a prime number
BaseRepresentation
bin1110011101100010010…
…00110000010010110001
31202111120100000220100211
413032301020300102301
531120114113214413
61020134115344121
750620321446424
oct7166110602261
91674510026324
10496893101233
11181805224471
12803745b2041
1337b1a578939
141a09a7519bb
15cdd2ec583d
hex73b12304b1

496893101233 has 2 divisors, whose sum is σ = 496893101234. Its totient is φ = 496893101232.

The previous prime is 496893101179. The next prime is 496893101239. The reversal of 496893101233 is 332101398694.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 471787649424 + 25105451809 = 686868^2 + 158447^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-496893101233 is a prime.

It is a super-2 number, since 2×4968931012332 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (496893101239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248446550616 + 248446550617.

It is an arithmetic number, because the mean of its divisors is an integer number (248446550617).

Almost surely, 2496893101233 is an apocalyptic number.

It is an amenable number.

496893101233 is a deficient number, since it is larger than the sum of its proper divisors (1).

496893101233 is an equidigital number, since it uses as much as digits as its factorization.

496893101233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 839808, while the sum is 49.

The spelling of 496893101233 in words is "four hundred ninety-six billion, eight hundred ninety-three million, one hundred one thousand, two hundred thirty-three".