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4968982522577 is a prime number
BaseRepresentation
bin100100001001110111001…
…1100000010101011010001
3122121000210221021000102002
41020103232130002223101
51122402434011210302
614322415152203345
71021666006360613
oct110235634025321
918530727230362
104968982522577
1116463741026a7
12683032239555
132a075ac82b28
14132700160db3
15893c4612c02
hex484ee702ad1

4968982522577 has 2 divisors, whose sum is σ = 4968982522578. Its totient is φ = 4968982522576.

The previous prime is 4968982522561. The next prime is 4968982522729. The reversal of 4968982522577 is 7752252898694.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4677253988416 + 291728534161 = 2162696^2 + 540119^2 .

It is a cyclic number.

It is not a de Polignac number, because 4968982522577 - 24 = 4968982522561 is a prime.

It is a super-3 number, since 3×49689825225773 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4968982522547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2484491261288 + 2484491261289.

It is an arithmetic number, because the mean of its divisors is an integer number (2484491261289).

Almost surely, 24968982522577 is an apocalyptic number.

It is an amenable number.

4968982522577 is a deficient number, since it is larger than the sum of its proper divisors (1).

4968982522577 is an equidigital number, since it uses as much as digits as its factorization.

4968982522577 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1219276800, while the sum is 74.

The spelling of 4968982522577 in words is "four trillion, nine hundred sixty-eight billion, nine hundred eighty-two million, five hundred twenty-two thousand, five hundred seventy-seven".