497113403 has 4 divisors (see below), whose sum is σ = 498498480. Its totient is φ = 495728328.

The previous prime is 497113399. The next prime is 497113417. The reversal of 497113403 is 304311794.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304311794 = 2 ⋅152155897.

It is a cyclic number.

It is not a de Polignac number, because 497113403 - 2² = 497113399 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 497113403.

It is not an unprimeable number, because it can be changed into a prime (497113453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 692000 + ... + 692717.

It is an arithmetic number, because the mean of its divisors is an integer number (124624620).

Almost surely, 2^497113403 is an apocalyptic number.

497113403 is a deficient number, since it is larger than the sum of its proper divisors (1385077).

497113403 is a wasteful number, since it uses less digits than its factorization.

497113403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1385076.

The product of its (nonzero) digits is 9072, while the sum is 32.

The square root of 497113403 is about 22296.0400744168. The cubic root of 497113403 is about 792.1701814983.

The spelling of 497113403 in words is "four hundred ninety-seven million, one hundred thirteen thousand, four hundred three".