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4971152803 is a prime number
BaseRepresentation
bin1001010000100110…
…11100010110100011
3110211110002201122111
410220103130112203
540140103342203
62141141020151
7234122046601
oct45023342643
913743081574
104971152803
1121210a4751
12b689b4657
13612b9b546
14352312871
151e165926d
hex1284dc5a3

4971152803 has 2 divisors, whose sum is σ = 4971152804. Its totient is φ = 4971152802.

The previous prime is 4971152783. The next prime is 4971152821. The reversal of 4971152803 is 3082511794.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4971152803 is a prime.

It is not a weakly prime, because it can be changed into another prime (4971152833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485576401 + 2485576402.

It is an arithmetic number, because the mean of its divisors is an integer number (2485576402).

Almost surely, 24971152803 is an apocalyptic number.

4971152803 is a deficient number, since it is larger than the sum of its proper divisors (1).

4971152803 is an equidigital number, since it uses as much as digits as its factorization.

4971152803 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 40.

The square root of 4971152803 is about 70506.4025674265. The cubic root of 4971152803 is about 1706.6810677945.

The spelling of 4971152803 in words is "four billion, nine hundred seventy-one million, one hundred fifty-two thousand, eight hundred three".