Base | Representation |
---|---|
bin | 1001010000100110… |
… | …11100010110100011 |
3 | 110211110002201122111 |
4 | 10220103130112203 |
5 | 40140103342203 |
6 | 2141141020151 |
7 | 234122046601 |
oct | 45023342643 |
9 | 13743081574 |
10 | 4971152803 |
11 | 21210a4751 |
12 | b689b4657 |
13 | 612b9b546 |
14 | 352312871 |
15 | 1e165926d |
hex | 1284dc5a3 |
4971152803 has 2 divisors, whose sum is σ = 4971152804. Its totient is φ = 4971152802.
The previous prime is 4971152783. The next prime is 4971152821. The reversal of 4971152803 is 3082511794.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4971152803 is a prime.
It is not a weakly prime, because it can be changed into another prime (4971152833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485576401 + 2485576402.
It is an arithmetic number, because the mean of its divisors is an integer number (2485576402).
Almost surely, 24971152803 is an apocalyptic number.
4971152803 is a deficient number, since it is larger than the sum of its proper divisors (1).
4971152803 is an equidigital number, since it uses as much as digits as its factorization.
4971152803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 40.
The square root of 4971152803 is about 70506.4025674265. The cubic root of 4971152803 is about 1706.6810677945.
The spelling of 4971152803 in words is "four billion, nine hundred seventy-one million, one hundred fifty-two thousand, eight hundred three".
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