Base | Representation |
---|---|
bin | 111000100000111111101001… |
… | …0000011001110111111100101 |
3 | 2102012010211002110101202221120 |
4 | 1301001333102003032333211 |
5 | 1010124221402443213013 |
6 | 4521135522551404153 |
7 | 206465304004656114 |
oct | 16101772203167745 |
9 | 2365124073352846 |
10 | 497115923804133 |
11 | 13443a7522249a7 |
12 | 47908491083659 |
13 | 1844caa46cba3a |
14 | 8aa877939dc7b |
15 | 3c711d5388123 |
hex | 1c41fd20cefe5 |
497115923804133 has 32 divisors (see below), whose sum is σ = 733606755628032. Its totient is φ = 297831801696000.
The previous prime is 497115923804117. The next prime is 497115923804147. The reversal of 497115923804133 is 331408329511794.
It is not a de Polignac number, because 497115923804133 - 24 = 497115923804117 is a prime.
It is a super-2 number, since 2×4971159238041332 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (497115923804153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 370432443 + ... + 371772008.
It is an arithmetic number, because the mean of its divisors is an integer number (22925211113376).
Almost surely, 2497115923804133 is an apocalyptic number.
It is an amenable number.
497115923804133 is a deficient number, since it is larger than the sum of its proper divisors (236490831823899).
497115923804133 is a wasteful number, since it uses less digits than its factorization.
497115923804133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 742205065.
The product of its (nonzero) digits is 19595520, while the sum is 60.
The spelling of 497115923804133 in words is "four hundred ninety-seven trillion, one hundred fifteen billion, nine hundred twenty-three million, eight hundred four thousand, one hundred thirty-three".
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