49720141 has 4 divisors (see below), whose sum is σ = 49734400. Its totient is φ = 49705884.

The previous prime is 49720127. The next prime is 49720147. The reversal of 49720141 is 14102794.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 14102794 = 2 ⋅7051397.

It is a cyclic number.

It is not a de Polignac number, because 49720141 - 2⁵ = 49720109 is a prime.

It is a super-4 number, since 4×49720141⁴ (a number of 32 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (49720147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1990 + ... + 10168.

It is an arithmetic number, because the mean of its divisors is an integer number (12433600).

Almost surely, 2^49720141 is an apocalyptic number.

It is an amenable number.

49720141 is a deficient number, since it is larger than the sum of its proper divisors (14259).

49720141 is an equidigital number, since it uses as much as digits as its factorization.

49720141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14258.

The product of its (nonzero) digits is 2016, while the sum is 28.

The square root of 49720141 is about 7051.2510237546. The cubic root of 49720141 is about 367.7145238929.

The spelling of 49720141 in words is "forty-nine million, seven hundred twenty thousand, one hundred forty-one".