Base | Representation |
---|---|
bin | 1001010000101110… |
… | …01110010111010001 |
3 | 110211111222002102111 |
4 | 10220113032113101 |
5 | 40140332102311 |
6 | 2141214145321 |
7 | 234133345612 |
oct | 45027162721 |
9 | 13744862374 |
10 | 4972144081 |
11 | 2121711493 |
12 | b691b2241 |
13 | 6131577b8 |
14 | 3524cdc09 |
15 | 1e17a2d21 |
hex | 1285ce5d1 |
4972144081 has 2 divisors, whose sum is σ = 4972144082. Its totient is φ = 4972144080.
The previous prime is 4972144031. The next prime is 4972144091. The reversal of 4972144081 is 1804412794.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3920763456 + 1051380625 = 62616^2 + 32425^2 .
It is a cyclic number.
It is not a de Polignac number, because 4972144081 - 29 = 4972143569 is a prime.
It is a super-2 number, since 2×49721440812 = 49444433524446669122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4972144031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2486072040 + 2486072041.
It is an arithmetic number, because the mean of its divisors is an integer number (2486072041).
Almost surely, 24972144081 is an apocalyptic number.
It is an amenable number.
4972144081 is a deficient number, since it is larger than the sum of its proper divisors (1).
4972144081 is an equidigital number, since it uses as much as digits as its factorization.
4972144081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 40.
The square root of 4972144081 is about 70513.4319190323. The cubic root of 4972144081 is about 1706.7945011049.
The spelling of 4972144081 in words is "four billion, nine hundred seventy-two million, one hundred forty-four thousand, eighty-one".
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