4974000011 has 2 divisors, whose sum is σ = 4974000012. Its totient is φ = 4974000010.

The previous prime is 4973999939. The next prime is 4974000019. The reversal of 4974000011 is 1100004794.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4974000011 - 2¹⁴ = 4973983627 is a prime.

It is a super-2 number, since 2×4974000011² = 49481352218856000242, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4974000019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2487000005 + 2487000006.

It is an arithmetic number, because the mean of its divisors is an integer number (2487000006).

Almost surely, 2^4974000011 is an apocalyptic number.

4974000011 is a deficient number, since it is larger than the sum of its proper divisors (1).

4974000011 is an equidigital number, since it uses as much as digits as its factorization.

4974000011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

The square root of 4974000011 is about 70526.5908080066. The cubic root of 4974000011 is about 1707.0068372063.

The spelling of 4974000011 in words is "four billion, nine hundred seventy-four million, eleven", and thus it is an aban number.