Base | Representation |
---|---|
bin | 1001010001000001… |
… | …01011101001011001 |
3 | 110211200122001022012 |
4 | 10220200223221121 |
5 | 40142000421241 |
6 | 2141343235305 |
7 | 234163412663 |
oct | 45040535131 |
9 | 13750561265 |
10 | 4974623321 |
11 | 2123055148 |
12 | b69ba8b35 |
13 | 6138150c5 |
14 | 352977533 |
15 | 1e1ae26eb |
hex | 12882ba59 |
4974623321 has 2 divisors, whose sum is σ = 4974623322. Its totient is φ = 4974623320.
The previous prime is 4974623309. The next prime is 4974623341. The reversal of 4974623321 is 1233264794.
4974623321 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3310391296 + 1664232025 = 57536^2 + 40795^2 .
It is a cyclic number.
It is not a de Polignac number, because 4974623321 - 214 = 4974606937 is a prime.
It is not a weakly prime, because it can be changed into another prime (4974623341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2487311660 + 2487311661.
It is an arithmetic number, because the mean of its divisors is an integer number (2487311661).
Almost surely, 24974623321 is an apocalyptic number.
It is an amenable number.
4974623321 is a deficient number, since it is larger than the sum of its proper divisors (1).
4974623321 is an equidigital number, since it uses as much as digits as its factorization.
4974623321 is an evil number, because the sum of its binary digits is even.
The product of its digits is 217728, while the sum is 41.
The square root of 4974623321 is about 70531.0096411500. The cubic root of 4974623321 is about 1707.0781379695.
The spelling of 4974623321 in words is "four billion, nine hundred seventy-four million, six hundred twenty-three thousand, three hundred twenty-one".
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