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4977490753 is a prime number
BaseRepresentation
bin1001010001010111…
…00111101101000001
3110211220000201200101
410220223213231001
540143214201003
62141524522401
7234226654564
oct45053475501
913756021611
104977490753
112124733524
12b6ab50401
136142aa301
143530c24db
151e1eac11d
hex128ae7b41

4977490753 has 2 divisors, whose sum is σ = 4977490754. Its totient is φ = 4977490752.

The previous prime is 4977490717. The next prime is 4977490799. The reversal of 4977490753 is 3570947794.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4059218944 + 918271809 = 63712^2 + 30303^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4977490753 is a prime.

It is a super-3 number, since 3×49774907533 (a number of 30 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4977490694 and 4977490703.

It is not a weakly prime, because it can be changed into another prime (4977490703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2488745376 + 2488745377.

It is an arithmetic number, because the mean of its divisors is an integer number (2488745377).

Almost surely, 24977490753 is an apocalyptic number.

It is an amenable number.

4977490753 is a deficient number, since it is larger than the sum of its proper divisors (1).

4977490753 is an equidigital number, since it uses as much as digits as its factorization.

4977490753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6667920, while the sum is 55.

The square root of 4977490753 is about 70551.3341688164. The cubic root of 4977490753 is about 1707.4060683451.

The spelling of 4977490753 in words is "four billion, nine hundred seventy-seven million, four hundred ninety thousand, seven hundred fifty-three".