Base | Representation |
---|---|
bin | 100100001111110011100… |
… | …0010100111111101000011 |
3 | 122122020202020221201212011 |
4 | 1020133213002213331003 |
5 | 1123110102242232044 |
6 | 14332325320313351 |
7 | 1022630146356352 |
oct | 110374702477503 |
9 | 18566666851764 |
10 | 4981743320899 |
11 | 165082225a314 |
12 | 6855b3912857 |
13 | 2a1a12923177 |
14 | 133190c21999 |
15 | 898bea65134 |
hex | 487e70a7f43 |
4981743320899 has 2 divisors, whose sum is σ = 4981743320900. Its totient is φ = 4981743320898.
The previous prime is 4981743320863. The next prime is 4981743320959. The reversal of 4981743320899 is 9980233471894.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4981743320899 - 215 = 4981743288131 is a prime.
It is not a weakly prime, because it can be changed into another prime (4981743320839) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2490871660449 + 2490871660450.
It is an arithmetic number, because the mean of its divisors is an integer number (2490871660450).
Almost surely, 24981743320899 is an apocalyptic number.
4981743320899 is a deficient number, since it is larger than the sum of its proper divisors (1).
4981743320899 is an equidigital number, since it uses as much as digits as its factorization.
4981743320899 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 94058496, while the sum is 67.
The spelling of 4981743320899 in words is "four trillion, nine hundred eighty-one billion, seven hundred forty-three million, three hundred twenty thousand, eight hundred ninety-nine".
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