Base | Representation |
---|---|
bin | 10110101010011101110011… |
… | …10000100001001101111001 |
3 | 20112110102121120101012110202 |
4 | 23111032321300201031321 |
5 | 23013014422220230132 |
6 | 253555030522051545 |
7 | 13332435506503202 |
oct | 1325167160411571 |
9 | 215412546335422 |
10 | 49837622039417 |
11 | 14975020416a53 |
12 | 570aa46949bb5 |
13 | 21a688a9161b4 |
14 | c44221d705a9 |
15 | 5b65ce551762 |
hex | 2d53b9c21379 |
49837622039417 has 2 divisors, whose sum is σ = 49837622039418. Its totient is φ = 49837622039416.
The previous prime is 49837622039371. The next prime is 49837622039453. The reversal of 49837622039417 is 71493022673894.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30449416573801 + 19388205465616 = 5518099^2 + 4403204^2 .
It is a cyclic number.
It is not a de Polignac number, because 49837622039417 - 26 = 49837622039353 is a prime.
It is not a weakly prime, because it can be changed into another prime (49837622039497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24918811019708 + 24918811019709.
It is an arithmetic number, because the mean of its divisors is an integer number (24918811019709).
Almost surely, 249837622039417 is an apocalyptic number.
It is an amenable number.
49837622039417 is a deficient number, since it is larger than the sum of its proper divisors (1).
49837622039417 is an equidigital number, since it uses as much as digits as its factorization.
49837622039417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 109734912, while the sum is 65.
The spelling of 49837622039417 in words is "forty-nine trillion, eight hundred thirty-seven billion, six hundred twenty-two million, thirty-nine thousand, four hundred seventeen".
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