Base | Representation |
---|---|
bin | 100100010010001100101… |
… | …0110011110100000000001 |
3 | 122122202000101221121211002 |
4 | 1020210121112132200001 |
5 | 1123201113340300103 |
6 | 14334535255501345 |
7 | 1023201410413601 |
oct | 110443126364001 |
9 | 18582011847732 |
10 | 4986882353153 |
11 | 1652a1a098308 |
12 | 6865a8987855 |
13 | 2a235151075c |
14 | 13351b554c01 |
15 | 89ac0cd1488 |
hex | 4891959e801 |
4986882353153 has 2 divisors, whose sum is σ = 4986882353154. Its totient is φ = 4986882353152.
The previous prime is 4986882353113. The next prime is 4986882353179. The reversal of 4986882353153 is 3513532886894.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4703918997904 + 282963355249 = 2168852^2 + 531943^2 .
It is a cyclic number.
It is not a de Polignac number, because 4986882353153 - 210 = 4986882352129 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4986882353153.
It is not a weakly prime, because it can be changed into another prime (4986882353113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2493441176576 + 2493441176577.
It is an arithmetic number, because the mean of its divisors is an integer number (2493441176577).
Almost surely, 24986882353153 is an apocalyptic number.
It is an amenable number.
4986882353153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4986882353153 is an equidigital number, since it uses as much as digits as its factorization.
4986882353153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 149299200, while the sum is 65.
The spelling of 4986882353153 in words is "four trillion, nine hundred eighty-six billion, eight hundred eighty-two million, three hundred fifty-three thousand, one hundred fifty-three".
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