Base | Representation |
---|---|
bin | 1001010010101100… |
… | …11011000110110011 |
3 | 110212200010210102221 |
4 | 10221112123012303 |
5 | 40204102230342 |
6 | 2143005221511 |
7 | 234424226644 |
oct | 45126330663 |
9 | 13780123387 |
10 | 4988711347 |
11 | 212aaa7744 |
12 | b72861897 |
13 | 616708609 |
14 | 3547a36cb |
15 | 1e2e76a67 |
hex | 12959b1b3 |
4988711347 has 2 divisors, whose sum is σ = 4988711348. Its totient is φ = 4988711346.
The previous prime is 4988711317. The next prime is 4988711401. The reversal of 4988711347 is 7431178894.
4988711347 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4988711347 - 215 = 4988678579 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4988711294 and 4988711303.
It is not a weakly prime, because it can be changed into another prime (4988711317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2494355673 + 2494355674.
It is an arithmetic number, because the mean of its divisors is an integer number (2494355674).
Almost surely, 24988711347 is an apocalyptic number.
4988711347 is a deficient number, since it is larger than the sum of its proper divisors (1).
4988711347 is an equidigital number, since it uses as much as digits as its factorization.
4988711347 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1354752, while the sum is 52.
The square root of 4988711347 is about 70630.8101822427. The cubic root of 4988711347 is about 1708.6880886377.
The spelling of 4988711347 in words is "four billion, nine hundred eighty-eight million, seven hundred eleven thousand, three hundred forty-seven".
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