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499326990103 = 1313811656413
BaseRepresentation
bin1110100010000100011…
…01010011011100010111
31202201211221211021020001
413101002031103130113
531140110202140403
61021215422152131
751034534246354
oct7210215233427
91681757737201
10499326990103
11182844083177
1280933722647
133811789b676
141a24bab362b
15cec69e2c1d
hex7442353717

499326990103 has 4 divisors (see below), whose sum is σ = 503138646648. Its totient is φ = 495515333560.

The previous prime is 499326990067. The next prime is 499326990133. The reversal of 499326990103 is 301099623994.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 499326990103 - 225 = 499293435671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (499326990133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905828076 + ... + 1905828337.

It is an arithmetic number, because the mean of its divisors is an integer number (125784661662).

Almost surely, 2499326990103 is an apocalyptic number.

499326990103 is a deficient number, since it is larger than the sum of its proper divisors (3811656545).

499326990103 is a wasteful number, since it uses less digits than its factorization.

499326990103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3811656544.

The product of its (nonzero) digits is 2834352, while the sum is 55.

The spelling of 499326990103 in words is "four hundred ninety-nine billion, three hundred twenty-six million, nine hundred ninety thousand, one hundred three".

Divisors: 1 131 3811656413 499326990103