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49986113 is a prime number
BaseRepresentation
bin1011111010101…
…1101001000001
310111001120001112
42332223221001
5100244023423
64543213105
71144606052
oct276535101
9114046045
1049986113
1126241341
12148a7195
13a481ca8
1468d2729
1545c5a78
hex2faba41

49986113 has 2 divisors, whose sum is σ = 49986114. Its totient is φ = 49986112.

The previous prime is 49986071. The next prime is 49986121. The reversal of 49986113 is 31168994.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39790864 + 10195249 = 6308^2 + 3193^2 .

49986113 is a truncatable prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-49986113 is a prime.

It is a super-2 number, since 2×499861132 = 4997222985697538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (49986163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24993056 + 24993057.

It is an arithmetic number, because the mean of its divisors is an integer number (24993057).

Almost surely, 249986113 is an apocalyptic number.

It is an amenable number.

49986113 is a deficient number, since it is larger than the sum of its proper divisors (1).

49986113 is an equidigital number, since it uses as much as digits as its factorization.

49986113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 46656, while the sum is 41.

The square root of 49986113 is about 7070.0857844866. The cubic root of 49986113 is about 368.3690399423.

It can be divided in two parts, 4998 and 6113, that added together give a palindrome (11111).

The spelling of 49986113 in words is "forty-nine million, nine hundred eighty-six thousand, one hundred thirteen".